16^x+1=128^2x+3

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Solution for 16^x+1=128^2x+3 equation: 



16^x+1=128^2x+3

We move all terms to the left:

16^x+1-(128^2x+3)=0

We get rid of parentheses

16^x-128^2x-3+1=0

We add all the numbers together, and all the variables

16^x-128^2x-2=0

We move all terms containing x to the left, all other terms to the right

16^x-128^2x=2

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